weirdfacts
Year 11 / Introduction to differential calculus

Let the secant become a tangent.

An average rate is the slope between two points: [f(x + h) − f(x)f(x)]/h. Let the spacing h approach zero to obtain the tangent gradient f(x)f'(x). The derivative is itself a function, so its value varies with x.

Expand before cancelling h, then take the limit. Substituting h = 0 too early creates 00\frac{0}{0}. For a positive integer n, the resulting power rule is d(xnx^{n})/dx = nxⁿ⁻¹; a constant differentiates to zero.

INTERACTIVE MODEL

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Function x³ − 3x, tangent and derivative-2.5-1.88-1.25-0.6300.631.251.882.5-5-1.751.54.758xy
f(x)f(x) = x3x^{3} − 3xtangentsecant
f′(1) = 0 · secant = 1.4749

The graph is calculated from the displayed rule. Drag the highlighted point or use the sliders.

Explore: Reduce the secant spacing towards zero and compare the secant gradient with the tangent gradient.

Derivative from first principles
f(x)=limh0f(x+h)f(x)hf'(x)=\lim_{h\to0}\frac{f(x+h)-f(x)}h
WORKED EXAMPLE

Differentiate f(x)f(x) = x2x^{2} from first principles.

  1. [f(x + h) − f(x)f(x)]/h = [(x + h)² − x2x^{2}]/h.
  2. For h ≠ 0 this simplifies to 2x2x + h.
  3. As h → 0, f(x)f'(x) = 2x2x.
Assumed knowledge

Gradient and expanding powers.

Learning checkpoints & sourceYOUR LEARNING CHECKPOINT
  • Compare average and instantaneous rates.
  • Differentiate a polynomial from first principles.
QCAA Mathematical Methods 2025 v1.3 · p. 21
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