Year 11 / Applications of differential calculus
Use the slope to read the curve.
At x = a, the tangent has gradient and passes through (a, ). If that gradient is non-zero, the normal gradient is −1/f′(a). A horizontal tangent has a vertical normal.
Stationary points have = 0. A change from positive to negative derivative gives a local maximum; negative to positive gives a local minimum. No sign change can give a stationary point of inflection. A global extremum on a closed interval also requires checking endpoints.
INTERACTIVE MODEL
Try it. Watch it change.
= − 3xtangent
The graph is calculated from the displayed rule. Drag the highlighted point or use the sliders.
Explore: Use the cubic model and locate where the tangent becomes horizontal. Compare the gradient on each side.
Tangent at x = a
Find the tangent to y = at x = 3.
- = 9 and = 6.
- y − 9 = 6(x − 3), so y = 6x − 9.
Assumed knowledge
Differentiation of polynomials and line equations.
Learning checkpoints & source
YOUR LEARNING CHECKPOINT- Find tangent and normal equations.
- Classify stationary points using gradient signs.
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