weirdfacts
Year 12 / Electromagnetism

A sideways force changes direction.

A moving charge in a magnetic field experiences force qvB sinθ\sin\theta, perpendicular to both velocity and field. Use a right-hand rule for a positive charge and reverse it for a negative one. A parallel velocity component experiences no magnetic force.

Because magnetic force is perpendicular to velocity, it changes direction without doing work on a point charge. For perpendicular entry into a uniform field the path is circular. A current-carrying wire has force BIL sinθ\sin\theta, using conventional current direction.

INTERACTIVE MODEL

Magnetic force depends on angle

READ THE GRAPH

Explore the relationship

Positive charge 1.60 × 10⁻¹⁹ C at 1.00 × 10⁶ m s⁻¹. Magnetic force is perpendicular to velocity.

Force / 10⁻¹⁴ N02.14.26.38.404590135180Angle between v and B / degrees
Force / 10⁻¹⁴ N

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View plotted data as a table
Explore the relationship
SeriesAngle between v and B / degreesForce / 10⁻¹⁴ N
Force / 10⁻¹⁴ N00
Force / 10⁻¹⁴ N30.418688
Force / 10⁻¹⁴ N60.836228
Force / 10⁻¹⁴ N91.25148
Force / 10⁻¹⁴ N121.66329
Force / 10⁻¹⁴ N152.07055
Force / 10⁻¹⁴ N182.47214
Force / 10⁻¹⁴ N212.86694
Force / 10⁻¹⁴ N243.25389
Force / 10⁻¹⁴ N273.63192
Force / 10⁻¹⁴ N304
Force / 10⁻¹⁴ N334.35711
Force / 10⁻¹⁴ N364.70228
Force / 10⁻¹⁴ N395.03456
Force / 10⁻¹⁴ N425.35304
Force / 10⁻¹⁴ N455.65685
Force / 10⁻¹⁴ N485.94516
Force / 10⁻¹⁴ N516.21717
Force / 10⁻¹⁴ N546.47214
Force / 10⁻¹⁴ N576.70936
Force / 10⁻¹⁴ N606.9282
Force / 10⁻¹⁴ N637.12805
Force / 10⁻¹⁴ N667.30836
Force / 10⁻¹⁴ N697.46864
Force / 10⁻¹⁴ N727.60845
Force / 10⁻¹⁴ N757.72741
Force / 10⁻¹⁴ N787.82518
Force / 10⁻¹⁴ N817.90151
Force / 10⁻¹⁴ N847.95618
Force / 10⁻¹⁴ N877.98904
Force / 10⁻¹⁴ N908
Force / 10⁻¹⁴ N937.98904
Force / 10⁻¹⁴ N967.95618
Force / 10⁻¹⁴ N997.90151
Force / 10⁻¹⁴ N1027.82518
Force / 10⁻¹⁴ N1057.72741
Force / 10⁻¹⁴ N1087.60845
Force / 10⁻¹⁴ N1117.46864
Force / 10⁻¹⁴ N1147.30836
Force / 10⁻¹⁴ N1177.12805
Force / 10⁻¹⁴ N1206.9282
Force / 10⁻¹⁴ N1236.70936
Force / 10⁻¹⁴ N1266.47214
Force / 10⁻¹⁴ N1296.21717
Force / 10⁻¹⁴ N1325.94516
Force / 10⁻¹⁴ N1355.65685
Force / 10⁻¹⁴ N1385.35304
Force / 10⁻¹⁴ N1415.03456
Force / 10⁻¹⁴ N1444.70228
Force / 10⁻¹⁴ N1474.35711
Force / 10⁻¹⁴ N1504
Force / 10⁻¹⁴ N1533.63192
Force / 10⁻¹⁴ N1563.25389
Force / 10⁻¹⁴ N1592.86694
Force / 10⁻¹⁴ N1622.47214
Force / 10⁻¹⁴ N1652.07055
Force / 10⁻¹⁴ N1681.66329
Force / 10⁻¹⁴ N1711.25148
Force / 10⁻¹⁴ N1740.836228
Force / 10⁻¹⁴ N1770.418688
Force / 10⁻¹⁴ N1809.79717e-16
Force / 10⁻¹⁴ N: 0

Explore: Change the angle through 0°, 90° and 180°. Find where force is zero and maximal.

F=qvBsinθF=BILsinθr=mvqBF=|q|vB\sin\theta\qquad F=BIL\sin\theta\qquad r=\frac{mv}{|q|B}
WORKED EXAMPLE

A 0.20 m wire carries 3 A perpendicular to a 0.50 T field.

  1. F = BIL sin 90°.
  2. F = 0.50 × 3 × 0.20 = 0.30 N.
Assumed knowledge

Centripetal force and sine.

Learning checkpoints & sourceYOUR LEARNING CHECKPOINT
  • Calculate magnetic force on charges and wires.
  • Explain circular charged-particle motion.
QCAA Physics · Unit 3 · Electromagnetism
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