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Year 11 / Linear motion and force

Draw forces on one object.

A free-body diagram includes external forces acting on one selected object: weight, normal force, tension, friction and applied forces as appropriate. Constant velocity requires zero net force, not zero individual forces.

Net force equals mass times acceleration. Newton’s third-law pair acts on different objects, so those two forces do not cancel on a single-object diagram. A normal force is perpendicular to the contact surface and need not always equal weight.

INTERACTIVE MODEL

A net force changes motion

25 N10 NNet force: 15 N · right is positive
READ THE GRAPH

Explore the relationship

Applied force points right; a fixed 10 N force points left. Right is positive.

Acceleration / m s⁻²03.9387.87511.8115.7513.255.57.7510Mass / kg
Acceleration / m s⁻²

Tap or focus a plotted point to read its values.

View plotted data as a table
Explore the relationship
SeriesMass / kgAcceleration / m s⁻²
Acceleration / m s⁻²115
Acceleration / m s⁻²1.1513.0435
Acceleration / m s⁻²1.311.5385
Acceleration / m s⁻²1.4510.3448
Acceleration / m s⁻²1.69.375
Acceleration / m s⁻²1.758.57143
Acceleration / m s⁻²1.97.89474
Acceleration / m s⁻²2.057.31707
Acceleration / m s⁻²2.26.81818
Acceleration / m s⁻²2.356.38298
Acceleration / m s⁻²2.56
Acceleration / m s⁻²2.655.66038
Acceleration / m s⁻²2.85.35714
Acceleration / m s⁻²2.955.08475
Acceleration / m s⁻²3.14.83871
Acceleration / m s⁻²3.254.61538
Acceleration / m s⁻²3.44.41176
Acceleration / m s⁻²3.554.22535
Acceleration / m s⁻²3.74.05405
Acceleration / m s⁻²3.853.8961
Acceleration / m s⁻²43.75
Acceleration / m s⁻²4.153.61446
Acceleration / m s⁻²4.33.48837
Acceleration / m s⁻²4.453.37079
Acceleration / m s⁻²4.63.26087
Acceleration / m s⁻²4.753.15789
Acceleration / m s⁻²4.93.06122
Acceleration / m s⁻²5.052.9703
Acceleration / m s⁻²5.22.88462
Acceleration / m s⁻²5.352.80374
Acceleration / m s⁻²5.52.72727
Acceleration / m s⁻²5.652.65487
Acceleration / m s⁻²5.82.58621
Acceleration / m s⁻²5.952.52101
Acceleration / m s⁻²6.12.45902
Acceleration / m s⁻²6.252.4
Acceleration / m s⁻²6.42.34375
Acceleration / m s⁻²6.552.29008
Acceleration / m s⁻²6.72.23881
Acceleration / m s⁻²6.852.18978
Acceleration / m s⁻²72.14286
Acceleration / m s⁻²7.152.0979
Acceleration / m s⁻²7.32.05479
Acceleration / m s⁻²7.452.01342
Acceleration / m s⁻²7.61.97368
Acceleration / m s⁻²7.751.93548
Acceleration / m s⁻²7.91.89873
Acceleration / m s⁻²8.051.86335
Acceleration / m s⁻²8.21.82927
Acceleration / m s⁻²8.351.79641
Acceleration / m s⁻²8.51.76471
Acceleration / m s⁻²8.651.7341
Acceleration / m s⁻²8.81.70455
Acceleration / m s⁻²8.951.67598
Acceleration / m s⁻²9.11.64835
Acceleration / m s⁻²9.251.62162
Acceleration / m s⁻²9.41.59574
Acceleration / m s⁻²9.551.57068
Acceleration / m s⁻²9.71.54639
Acceleration / m s⁻²9.851.52284
Acceleration / m s⁻²101.5
Acceleration / m s⁻²: 15

Explore: Vary the applied force across the opposing force and watch the acceleration reverse.

Fnet=maFg=mgF_{\rm net}=ma\qquad F_g=mg
WORKED EXAMPLE

A 4 kg cart is pulled right with 18 N while friction is 6 N left.

  1. Net force = 18 − 6 = 12 N right.
  2. a = 124\frac{12}{4} = 3 ms2\mathrm{m}\,\mathrm{s}^{-2} right.
Assumed knowledge

Vectors in one dimension.

Learning checkpoints & sourceYOUR LEARNING CHECKPOINT
  • Apply Newton’s three laws.
  • Use free-body diagrams and net force.
QCAA Physics · Unit 2 · Linear motion and force
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