weirdfacts

The derivative of lnx\ln x is 1x\frac{1}{x} on x>0x>0. Applying the chain rule gives g(x)g(x)\frac{g'(x)}{g(x)} for ln(g(x))\ln(g(x)), wherever g(x)g(x) is positive. State this real domain alongside a derivative.

Because ln and exp are inverse functions, ln(ex)\ln(e^x) = x and elnxe^{\ln x} = x for x>0x>0. Taking logarithms solves exponential equations. The derivative measures local sensitivity: equal absolute input changes have larger effects when x is small.

INTERACTIVE MODEL

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Function ln(x), tangent and derivative-2.5-1.88-1.25-0.6300.631.251.882.5-5-1.751.54.758xy
f(x)f(x) = ln(x)\ln(x)tangentf(x)f'(x)
f′(1) = 1 · f″(1) = -1

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Explore: Select ln(x)\ln(x). Move towards zero from the right and observe how its tangent steepens.

Chain rule for logarithms
ddxlng(x)=g(x)g(x)\frac{\mathrm d}{\mathrm dx}\ln g(x)=\frac{g'(x)}{g(x)}
Real domain
g(x)>0g(x)>0
WORKED EXAMPLE

Differentiate f(x)f(x) = ln(5x2)\ln(5x-2) and give its domain.

  1. 5x − 2 > 0 requires x > 25\frac{2}{5}.
  2. f(x)f'(x) = 55x2\frac{5}{5x-2} on this domain.
Assumed knowledge

Logarithm laws, inequalities and chain rule.

Learning checkpoints & sourceYOUR LEARNING CHECKPOINT
  • Differentiate logarithmic composites.
  • Use the inverse relationship between ln and exp.
QCAA Mathematical Methods 2025 v1.3 · p. 24
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