weirdfacts

A probability density must be non-negative and integrate to one over its support. The density height is not itself a probability; a height can exceed one. Probability over an interval is the area under the density.

For a continuous variable, the probability at one exact point is zero. The cumulative distribution F(x) gives P(X ≤ x) and is non-decreasing. Expectation integrates x f(x)f(x); variance can be found using E(X2X^{2}) − μ².

INTERACTIVE MODEL

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Density f(x) = 2x on [0, 1]00.130.250.380.50.630.750.88100.631.251.882.5xy
f(x)f(x) = 2x2x
P(0 ≤ X ≤ 0.4) = 0.16

Density is zero outside [0, 1]. A shaded interval gives probability; a single point has probability zero.

Explore: Slide the upper bound and compare the shaded area with the cumulative probability.

Interval probability
P(aXb)=abf(x)dxP(a\le X\le b)=\int_a^b f(x)\,\mathrm dx
WORKED EXAMPLE

The density is f(x)f(x) = 2x2x for 0 ≤ x ≤ 1. Find P(X ≤ 0.5).

  1. Integrate from 0 to 0.5: [x2x^{2}]₀^0.5.
  2. The probability is 0.25.
Assumed knowledge

Definite integrals and probability rules.

Learning checkpoints & sourceYOUR LEARNING CHECKPOINT
  • Validate a density and calculate interval probabilities.
  • Find expectation and use a cumulative distribution.
QCAA Mathematical Methods 2025 v1.3 · p. 29
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