weirdfacts
Year 10 / Algebra foundations

Where two conditions meet.

A simultaneous solution must satisfy both equations. Substitution replaces one variable using another equation. Elimination adds or subtracts suitable multiples so one variable cancels.

On a graph, the solution is the intersection of the two lines. Parallel distinct lines have no solution; equations describing the same line have infinitely many. Always substitute the proposed pair back into both original conditions.

INTERACTIVE MODEL

Try it. Watch it change.

y = 1x + 0-4-3-2-101234-6-3036xy
y = 1x + 0y = −x + 2
f(1) = 1

The graph is calculated from the displayed rule. Drag the highlighted point or use the sliders.

Explore: Turn on the comparison line y = −x + 2. Adjust your line until the intersection lies on the y-axis.

A common solution
Both equations hold at the same (x,y).\text{Both equations hold at the same }(x,y).
WORKED EXAMPLE

Solve x + y = 9 and 2x2x − y = 3.

  1. Add the equations: 3x = 12, so x = 4.
  2. Substitute: y = 9 − 4 = 5.
  3. Check 2(4) − 5 = 3.
Assumed knowledge

Rearranging equations and handling negative signs.

Learning checkpoints & sourceYOUR LEARNING CHECKPOINT
  • Solve two linear equations together.
  • Interpret their intersection in a practical problem.
Year 10 preparation
READY TO TRY IT?

Put the idea to work.

Loading progress…