weirdfacts

Reduction potentials are tabulated against the standard hydrogen electrode, assigned 0 V. The more positive reduction potential is favoured for reduction when the two half-cells are connected under standard conditions.

E°cell = E°cathode − E°anode using reduction potentials for both. Do not multiply electrode potentials when multiplying a half-equation: voltage is not proportional to the amount of substance.

A positive E°cell predicts thermodynamic feasibility in the written direction under the stated standard conditions, commonly 298 K, 1 M solutions and 100 kPa gases. It does not guarantee a fast observable reaction or the same voltage under different conditions.

INTERACTIVE MODEL

Follow the electrons

salt bridgee⁻ →← anionscations →− Anode: oxidation+ Cathode: reductionZn → Zn²⁺ + 2e⁻Cu²⁺ + 2e⁻ → Cu
E°cell = 1.10 V · Current can flow

Metal/Cu galvanic cell under standard conditions. Ion and electron movement is schematic. The salt bridge carries ions; the external wire carries electrons.

Explore: Compare half-cells and use their standard potentials to predict the spontaneous direction.

E°cell = E°reduction(cathode) − E°reduction(anode)
WORKED EXAMPLE

E°(Cu²⁺/Cu) = +0.34 V and E°(Zn²⁺/Zn) = −0.76 V. Calculate E° for the spontaneous cell.

  1. E°cell = 0.34 − (−0.76).
  2. E°cell = +1.10 V.

Answer: 1.1 V

Assumed knowledge

Subtract signed numbers; values below are standard reduction potentials.

Learning checkpoints & sourceYOUR SYLLABUS CHECKPOINT
  • Calculate E°cell from reduction potentials.
  • Predict spontaneous direction under standard conditions.
  • Recognise the limits of standard predictions.
QCAA Chemistry 2025 v1.3 · p. 36 ↗
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